Convert regex '\Z' to '$'
See https://github.com/swagger-api/swagger-editor/issues/1601.
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@@ -211,7 +211,14 @@ def find_regex(regex_field):
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regex_validator = validator
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# regex_validator.regex should be a compiled re object...
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return getattr(getattr(regex_validator, 'regex', None), 'pattern', None)
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pattern = getattr(getattr(regex_validator, 'regex', None), 'pattern', None)
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if pattern:
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# attempt some basic cleanup to remove regex constructs not supported by JavaScript
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# -- swagger uses javascript-style regexes - see https://github.com/swagger-api/swagger-editor/issues/1601
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if pattern.endswith('\\Z') or pattern.endswith('\\z'):
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pattern = pattern[:-2] + '$'
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return pattern
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numeric_fields = (serializers.IntegerField, serializers.FloatField, serializers.DecimalField)
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@@ -162,9 +162,7 @@ class SwaggerAutoSchema(ViewInspector):
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default_status = guess_response_status(method)
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default_schema = ''
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if method == 'post':
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default_schema = self.get_request_serializer() or self.get_view_serializer()
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elif method in ('get', 'put', 'patch'):
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if method in ('get', 'post', 'put', 'patch'):
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default_schema = self.get_request_serializer() or self.get_view_serializer()
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default_schema = default_schema or ''
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