Infer ChoiceField type from model field when in ModelSerializer

Fixes part of issue #69
This commit is contained in:
Cristi Vîjdea
2018-02-26 20:31:12 +02:00
parent 3f7ad62950
commit ee46f59fb1
7 changed files with 67 additions and 13 deletions
+20 -9
View File
@@ -397,16 +397,27 @@ class ChoiceFieldInspector(FieldInspector):
def field_to_swagger_object(self, field, swagger_object_type, use_references, **kwargs):
SwaggerType, ChildSwaggerType = self._get_partial_types(field, swagger_object_type, use_references, **kwargs)
if isinstance(field, serializers.MultipleChoiceField):
return SwaggerType(
type=openapi.TYPE_ARRAY,
items=ChildSwaggerType(
type=openapi.TYPE_STRING,
enum=list(field.choices.keys())
if isinstance(field, serializers.ChoiceField):
enum_type = openapi.TYPE_STRING
# for ModelSerializer, try to infer the type from the associated model field
serializer = get_parent_serializer(field)
if isinstance(serializer, serializers.ModelSerializer):
model = getattr(getattr(serializer, 'Meta'), 'model')
model_field = get_model_field(model, field.source)
if model_field:
enum_type = get_basic_type_info(model_field).get('type', enum_type)
if isinstance(field, serializers.MultipleChoiceField):
return SwaggerType(
type=openapi.TYPE_ARRAY,
items=ChildSwaggerType(
type=enum_type,
enum=list(field.choices.keys())
)
)
)
elif isinstance(field, serializers.ChoiceField):
return SwaggerType(type=openapi.TYPE_STRING, enum=list(field.choices.keys()))
return SwaggerType(type=enum_type, enum=list(field.choices.keys()))
return NotHandled